Solubility of Salts Containing the Ions  Shown
Ion contained in the compound Solubility Exceptions
Group IA (Li+, Na+, K+, Rb+, Cs+) and NH4+  Soluble none
Nitrates (NO3-) and acetates (C2H3O2-) Soluble none
Chlorides (Cl-), bromides (Br-), and iodides (I-) Soluble Ag+, Pb2+, Hg22+
Sulfates (SO42-) Soluble Ba2+, Ca2+, Pb2+, Hg2+
Carbonates (CO32-) and phosphates (PO43-) Insoluble1 Group IA and NH4+ 
Chromate (CrO42-) and oxalates (C2O42-) Insoluble Group IA and NH4+ 
Sulfides (S2-) and oxides (O2-) Insoluble Group IA, IIA and NH4+ 
Hydroxides (OH- ) Insoluble Group IA, Ba2+, Sr2+, Ca2+

1All ionic compounds, even the least soluble ones, dissolve to some slight extent in water.  Thus, the "Insoluble" classification really means ionic compounds that have very limited solubility in water.  Remember that salts containing the "Insoluble" anions are always soluble with Group IA metals and ammonium ions.


Balancing Redox (Oxidation-Reduction) Reactions

After you identify the elements (or compounds) that will be oxidized or reduced, set up two half-reactions, one for oxidation (loss of electrons) and for reduction (gain of electrons).  You do not need to determine which one is oxidation or reduction, but you need to identify the correct compounds, or elements, that change oxidation state.

  1. Balance the number of atoms1
  2. Balance the number of oxygen atoms by adding water2
  3. Balance the number of hydrogen atoms by adding H+ (protons)3
  4. Balance charge by adding electrons (e-) to the side with the most positive (least negative) charge4
  5. Balance the number of electrons gained and electrons lost5
  6. For reactions in base (OH-), as your last step, add OH- ions to each side to convert H+'s into water

1Balance the non-oxygen and non-hydrogen atoms, which are usually those undergoing oxidation or reduction
2Add water to make the number of O-atoms the same on both sides
3Add H+ to make number of H-atoms the same on both sides
4Determine the charge on each side; add enough electrons to make charge same on both sides (electrons added to least negative side, or most positive side).
5If necessary multiply each reaction by an interger to give same number of electrons gained and lost

Example Redox Balancing:

Reaction to Balance: Cu + HNO3 Cu2+ + NO2
Copper Half Reaction: Cu Cu2+ + 2e-
Nitrogen Half Reaction: 1e- + H+ + HNO3 NO2 + H2O  or  x2 (1e- + H+ + HNO3 NO2 + H2O)
Final Nitrogen Half Reaction: 2e- + 2H+ + 2HNO3 2NO2 + 2H2O
Final Equation: Cu + 2H+ + 2HNO3 Cu2+  2NO2 + 2H2O