Experiment 8

Thermochemistry - Enthalpy of Neutralization

In this experiment you will mix an acid (hydrochloric, sulfuric or phosphoric acid) and a base (NaOH) and measure the heat of reaction (enthalpy of neutralization; ΔHrxn) for this titration reaction.  After you determine the amount of heat produced in your experiment, you will calculate the heat produced for each mole of water formed.

The acid solution that you will use for this experiment will be either 2M HCl, 1M H2SO4, or 0.667M H3PO4.  Do not be concerned that the concentrations of these acids are different, because the amount of water (H2O) formed in each reaction will be the same, 0.200 moles.  Since the concentration of protons (H+ ions) in each acid solution is 2.000 M, equal volumes of these solutions (100 mL) will produce the same amount of water (0.200 moles).  You will be assigned which acid you will use.  There will be an excess of OH- (hydroxide) ions (>0.200 M) in the NaOH solution.

A description of how to do the experiment is contained in your published protocols.  During the first day of this lab, you will do your calorimetry experiments by hand and calculate the heat of reaction for each of your experiments.  The information included here is supplemental to the published protocol and describes some of the analyses you will perform.  If you were assigned to use sulfuric acid, the following equation shows your reaction, and the theoretical heat of reaction (enthalpy of neutralization; you should calculate the DHrxn for this reaction to verify the heat of reaction shown).

H2SO4 (aq) + 2 NaOH (aq) 2 H2O (l) + Na2SO4 (aq)  

ΔHrxn = -110.0 kJ

Please note that the heat of reaction  (ΔHrxn) for this reaction is -110 kJ, and is for the synthesis of two (2) moles of water, not just one.  In fact, when you determine the heat of reaction for the other two acids used in this experiment (phosphoric and hydrochloric acids), you will produce different amounts of water for each reaction.  You should complete the reactions for the other two acids, and show your results in the table below (the balanced equation and heats of reaction are shown for sulfuric acid).  In order to compare the reaction enthalpies for each acid, you need to divide the calculated heat of reaction by the number of moles of water actually produced.  The values you determine are the theoretical heats of reaction for each of the acids used in these experiments, and should be close to each other, although not identical.

Table 1
Reaction ΔHrxn ΔH/mol H2O

H2SO4 (aq) + 2 NaOH (aq)2 H2O (l) + Na2SO4 (aq)  

-110.0 kJ

-55.0 kJ

HCl (aq) + NaOH (aq)

kJ

kJ

H3PO4 (aq) + NaOH (aq)

kJ

kJ

Use the values in Table 2 to calculate the heat of reaction for the other two acids. The values you calculater here for the ΔH/mol H2O will be used for your percent error calculations.

Table 2

Substance

ΔHfo (kJ/mol)

Substance

ΔHfo (kJ/mol)

NaOH (aq)

-469.6

NaCl (aq)

-407.1

HCl (aq)

-167.2

Na3PO4 (aq)

-2003.05

H3PO4 (aq)

-1288.3

Na2SO4 (aq)

-1386.8

H2SO4 (aq)

-909.3

H2O (l)

-285.85

Please remember that for your experiments, you will actually produce the same amount of water (0.200 moles) regardless of which acid is used in your experiment.  It is for this reason that you must adjust the heat of reaction for each of the reactions above, to adjust for the number of moles of water formed.  Since you will produce 0.200 moles of water in each of your experiments, after you determine the amount of heat produced in each of your individual reactions, you must multiply the observed enthalpy of neutralization by 5 (five) to calculate the amount of heat produced for each mole (1.00 moles) of water formed.   To determine the ΔHrxn (heat of reaction) for each of your individual experiments, use the equations shown in Table 4.  After you calculate your observed values, calculate the ΔH for each mole of water formed (multiply the ΔHrxn by 5 [or divide by 0.200]).  Calculate the ΔHrxn for each of your reactions in the same manner.

Table 3 (Show your actual data in this table)
Acid used in reaction (fill in only for the acid you used) ΔHrxn (qp = SH x mass x ΔT) ΔH/mol H2O

H2SO4 (aq)

kJ

kJ

kJ

kJ

HCl (aq)

kJ

kJ

kJ

kJ

H3PO4 (aq) 

kJ

kJ

kJ

kJ

Using the chart above, enter the value for the experiment results you obtained, but only for the acid that you used using the equation shown. Remember that qwater = - qreaction

The equations and information you will need are shown below (ΔHrxn = qp)

Table 4
qp = SH x mass x ΔT
  • SH = 4.184 J/goC (specific heat of water; Cp)
  • mass = 200 g (mass of acid [100 mL] and NaOH [100 mL] combined)
  • ΔT = Tf -Ti (final temperature - initial temperature of reaction)

Experimental Procedure

To do your experiment follow the instructions listed below.

After you have finished each of your two titration experiments, calculate the heat of reaction for each.  After you have determined the enthalpies of reaction for these experiments and have calculated the ΔH for the synthesis of one mole of water, enter these experimental values into the spreadsheet.  Be sure to enter your experimental values in the correct section of the spreadsheet, and enter the values for synthesis of one mole of water.

Calculation of experimental error.

In order to calculate your experimental error for each of your reactions, use the equation below.  The theoretical value is the heat of reaction, for your acid, per mole of water formed, shown in Table 1.  The experimental value is the actual heat of reaction you determined in each of your experiments (per mole of water formed).

To obtain %Error for a measurement, you need to know the Theoretical and Experimental values for your measurement, or set of calculations.  Use this formula to obtain the %Error, which is always a positve (absolute) value.

Computer-assisted calorimetry

The collection of the calorimetric data in this part of the experiment (second day of lab) will be performed using LabWorks.  An explanation of this procedure will be described in lab.  The analysis of your data will be performed during the next lab period.


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